0.999~ = 1. Prove me wrong.

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AuthorTopic: 0.999~ = 1. Prove me wrong.
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x=.9~
10x=9.9~
9x=10x-x
9.9~-.9~=9.
9=9x
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Not this conversation again. You're right, of course, since infinitesimals aren't defined in standard mathematics.

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There is no mathematical proof for .x~ - .x~ = 0 for this very reason.

I suppose next you are going to propose that we multiply infinity by zero.

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Or that 1=2 (which has actually been proved before mathematically).

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Not without invoking fuzzy math.

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It all depends on your axioms. If you assume that 0 = 1, proving that 1 = 2 is trivial.

And more accurately, one should say that the limit of .999 repeating is equal to 1, not that .999 repeating is itself equal to 1.

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...b10010b...
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Well, repeating decimals are really just a notation for fractions which can't be expressed in base 10. We wouldn't have to consider their limits unless they were actually equations, which I don't think they are.

Regarding the "proofs" of 1 = 2, all of them contain a division step which isn't mathematically valid if the divisor is 0 (which it has to be for the "proof" to work).

[ Friday, September 10, 2004 17:17: Message edited by: Thuryl ]

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Or this:

1/3 = .3~
2/3 = 1/3 + 1/3 = .3~ + .3~ = .6~
3/3 = 1 = 1/3 + 1/3 + 1/3 = .3~ + .3~ + .3~ = .9~

The base of numbers really does mess things up, doesn't it? In base 3, 10/3 = .1!

EDIT: Wait, I can prove you wrong. When dealing with any real number, a base is just a representation of numbers.

Since the symmetrical reflexive property would say that x = x, no matter the base.

Note that .1~ is 1/9, but I'll use 1/3 because of familiarity.

IN BASE 3:

1/10 = (10/10)/10 = 1 / 10 = .1 Definition of division and the converse of the identity property of multiplication

1/10 * 10 = 1/1 = 1 =
1/10 + 1/10 + 1/10 = .1 + .1 + .1 = 1!!

[ Friday, September 10, 2004 17:27: Message edited by: Garrison ]

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12 posts and I hate him already.

[ Friday, September 10, 2004 18:24: Message edited by: Wolfiewoobles ]

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quote:
Originally written by Fear Uncertainty and Custer:

There is no mathematical proof for .x~ - .x~ = 0 for this very reason.
.x~ (in the decimal system) is a representation of the rational number x/9. Each rational number has exactly one additive inverse.
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quote:
Originally written by SpaceOfAdes1134:

x=.9~
10x=9.9~
9x=10x-x
9.9~-.9~=9.
9=9x

It would be rather hard to explain this math problem because I don't believe there is any rational number that can be expressed as (.9~).

Also, what kind of name is SpaceOfAdes????

[ Saturday, September 11, 2004 06:57: Message edited by: Garrison ]

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You can look here.

Apparently the proof has a flaw, so I guess I was wrong in the first place. It looks pretty convincing, though.

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quote:
Also, what kind of name is SpaceOfAdes????
SpaceOfAdes = Ace of Spades.. Ace of Spades is my little nickname among my friends, and most places already have someone called "Ace of Spades", so I became SpaceOfAdes.

[ Sunday, September 12, 2004 13:11: Message edited by: SpaceOfAdes1134 ]
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Hmmm, rhetorical question.

That was a nice classical fallacy you posted, Ben. It was simple as long as you replace all the b variables with the letter a.

[ Saturday, September 11, 2004 19:01: Message edited by: Garrison ]

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0.9~ is equal to 1. It's defined as the limit of 9/10 + 9/100 + 9/1000 + ... as the number of terms goes to infinity, and that limit is exactly 1.

0.9~ - 0.9~ is defined, and is zero.

1 - 0.9~ is also zero, exactly.

0.0000...001 doesn't mean anything.

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